29x+3x^2=35

Solution for 29x+3x^2=35 equation:

29x+3x^2=35

We move all terms to the left:

29x+3x^2-(35)=0

a = 3; b = 29; c = -35;
Δ = b2-4ac
Δ = 292-4·3·(-35)
Δ = 1261
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29)-\sqrt{1261}}{2*3}=\frac{-29-\sqrt{1261}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29)+\sqrt{1261}}{2*3}=\frac{-29+\sqrt{1261}}{6}
$